Quote:
Originally Posted by jjblue1
Wikipedia has a page about goldbars, how big they should be and how much they should weight, if someone wants to have fun calculating how much space Kinzo's gold should take.
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This appears to be the standard for international ingot sizes. Thus, each ingot should be 12kg and measure about 250mm long, 70mm wide, and 35mm high. Let's assume "10 tons" is metric tons; there are therefore approximately 834 bars total. Let's make it an even 840.
Let's assume Kinzo stacks them 12-tall (meaning 70 bars per layer) and "square" (35x35 though it isn't actually square because the ingots aren't). The pile would be 8.75m long, 2.45m wide, 0.42m tall. If we make it taller by making it 20-tall (42 bars per layer) it'd be 5.25m long, 1.47m wide, and 0.70m tall. To even break 1m in height would require the pile be about 29 bars tall, which only gives 29 bars per layer, which is 3.75m long and 1.12m wide.
If you put it on a 1m tall pedestal and displayed the pile lengthwise (so the bars are seen side-on), it would look
reasonably impressive, but the pile still can't be that huge. If you square it off it could be about 2m by 2m by 1m or so. It would not tower over anybody unless it was stacked enough that it wouldn't be much more than 1m to a side, which is not
that impressive.
Incidentally, each bar would be worth ¥27,898,640 or $165,550.91. The total value of the entire pile is ¥23,434,857,600 or $139,062,764.40. As of Friday, the value of the pile would be $540,633,114.