Quote:
Originally Posted by Cyrus17
Isn't it dangerous to create tiny black holes? I heard one such thing can suck up enough matter beyond its events horizon (I think it's marked yellow) to destroy Switzerland and half the France under certain circumstances.
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This isn't Asura Cryin.
Spoiler for Science lesson for black hole:
Scientifically, black holes need a critical mass, or rather critical density to collapse infinitely. The large amount mass is to be confined within a circle with a standard radius known as the Schwartzchild radius.
A black hole is theoretically formed by superlarge stars exploding at the end of their lives, when they finished fusing their hydrogen into helium. It will then proceed to blow itself apart, before collapsing back in due to the speed in which it blows off the stuff at the top and creating a vacuum, in which in this case, hydrostatic pressure is unable to keep it at equilibrium.
According to Newton's law of Gravitation, a larger mass would exert a gravitational force on the smaller masses, and since the core has a larger combined mass in total, it starts pulling the particles it has blown off into itself to retain hydrostatic equilibrium. The vacuum offers little resistance and thus the particles accelerate at extremely high speeds towards the core and colliding with the core's particles and forming superdense subatomic particles.
As the total mass of the "core" increases over time, gravitational field strength increases, and thus increasing the acceleration of the particles towards the centre and further crushing masses together, allowing only light to escape. Eventually, the original core reaches a critical mass by the immense pressure of the particles being crushed outside and starts collapsing onto itself (for unknown reasons) and create a black hole as a result.
In the LHC, a similar concept applies as two particles are blasted at each other at high speeds. Due to the
Principle Conservation of Energy, combined with threshold energy level of the protons, it breaks up into smaller pieces, which is what the scientists want. Unfortunately, since this test takes place in an almost ideal environment, the
Ideal Gas law can be applied, thus the application of the
hydrostatic equilibrium and
gravitational collapse.
However for a micro black hole to be formed, the total particles must be compressed within this Schwartzchild radius :
R =
2G (Mass of 2 protons) /
(speed of light^2)
=
2 (6.67428+/-0.00067 * 10^-11) (2 * 1.672621637 * 10^-27) /
(9*10^16)
I calculated the radius to be
4.961575618 * 10^-54 < R <
4.962073687 * 10^-54 metres.
The total surface area of the black hole is between
3.117449902 * 10^-53 < A <
3.117762848 * 10^-53 sq metres.
The gravitational field strength from the event horizon is taken as
g =
G (theoretical mass of black hole at moment of formation) /
Schwartzchild radius^2
Since the theoretical mass of the black hole at moment of formation is assumed to be the total mass of protons due to being in the vicinity at the moment of gravitational collapse, the gravitational field strength is
4.533939433 * 10^69 < g <
9.070609984 * 10^69 newtons per kg.
However, the large hadron collider has a tunnel with diameter 27000 metres wide, the gravitational field strength at the point of the internal surface of the tunnel will be
1.225080399 * 10^-36 < g <
1.225203380 * 10^-36 newtons per kg, a negligibly small value.
In order to further increase its gravitational force, the micro black hole has to increase its mass. However, it is
unable to even exert a decent force to pull particles off the walls of the collider to fatten itself due to the
combined magnetic, gravitational, electric and nuclear forces that held the atoms on the surface together.
Secondly, the vacuum inside the collider prevents the micro black hole from appropriating any kind of physical mass to grow itself. There may be a possibility that it may absorb energy and convert it to mass, but the
Zeroth law of thermodynamics, combined with
Le Chatelier's Principle, requires the black hole to be in thermal equilibrium, and thus it will emit radiation to compensate for the energy absorbed.
Thirdly, as a black hole is known as an unstable mass, it will attempt to stabilise itself by emitting Hawking radiation. The time for the
black hole to evaporate is
3.925190770 * 10^-53 < t <
3.925978873 * 10^-53 seconds.
If none of the calculations above are wrong, I have proven outside of Murphy's law that the experiment is perfectly safe.