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Old 2009-11-24, 13:16   Link #4719
SaintessHeart
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Join Date: Nov 2007
Age: 35
Quote:
Originally Posted by Cyrus17 View Post
Isn't it dangerous to create tiny black holes? I heard one such thing can suck up enough matter beyond its events horizon (I think it's marked yellow) to destroy Switzerland and half the France under certain circumstances.
This isn't Asura Cryin.
Spoiler for Science lesson for black hole:


In the LHC, a similar concept applies as two particles are blasted at each other at high speeds. Due to the Principle Conservation of Energy, combined with threshold energy level of the protons, it breaks up into smaller pieces, which is what the scientists want. Unfortunately, since this test takes place in an almost ideal environment, the Ideal Gas law can be applied, thus the application of the hydrostatic equilibrium and gravitational collapse.

However for a micro black hole to be formed, the total particles must be compressed within this Schwartzchild radius :

R = 2G (Mass of 2 protons) / (speed of light^2)
= 2 (6.67428+/-0.00067 * 10^-11) (2 * 1.672621637 * 10^-27) / (9*10^16)

I calculated the radius to be 4.961575618 * 10^-54 < R < 4.962073687 * 10^-54 metres.

The total surface area of the black hole is between 3.117449902 * 10^-53 < A < 3.117762848 * 10^-53 sq metres.

The gravitational field strength from the event horizon is taken as

g = G (theoretical mass of black hole at moment of formation) / Schwartzchild radius^2

Since the theoretical mass of the black hole at moment of formation is assumed to be the total mass of protons due to being in the vicinity at the moment of gravitational collapse, the gravitational field strength is 4.533939433 * 10^69 < g < 9.070609984 * 10^69 newtons per kg.

However, the large hadron collider has a tunnel with diameter 27000 metres wide, the gravitational field strength at the point of the internal surface of the tunnel will be 1.225080399 * 10^-36 < g < 1.225203380 * 10^-36 newtons per kg, a negligibly small value.

In order to further increase its gravitational force, the micro black hole has to increase its mass. However, it is unable to even exert a decent force to pull particles off the walls of the collider to fatten itself due to the combined magnetic, gravitational, electric and nuclear forces that held the atoms on the surface together.

Secondly, the vacuum inside the collider prevents the micro black hole from appropriating any kind of physical mass to grow itself. There may be a possibility that it may absorb energy and convert it to mass, but the Zeroth law of thermodynamics, combined with Le Chatelier's Principle, requires the black hole to be in thermal equilibrium, and thus it will emit radiation to compensate for the energy absorbed.

Thirdly, as a black hole is known as an unstable mass, it will attempt to stabilise itself by emitting Hawking radiation. The time for the black hole to evaporate is 3.925190770 * 10^-53 < t < 3.925978873 * 10^-53 seconds.

If none of the calculations above are wrong, I have proven outside of Murphy's law that the experiment is perfectly safe.
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Last edited by SaintessHeart; 2009-11-24 at 13:33.
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